How to solve 3 imes(2-x) < -9

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3\times(2-x) < -9 | Equatix

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$$3 \times (2-x) < -9$$

$x>5$

Divide both sides by $3$. Since $3$ is positive, the inequality direction remains the same.

$$2-x<\frac{-9}{3}$$

Divide $-9$ by $3$ to get $-3$.

$$2-x<-3$$

Subtract $2$ from both sides.

$$-x<-3-2$$

Subtract $2$ from $-3$ to get $-5$.

$$-x<-5$$

Divide both sides by $-1$. Since $-1$ is negative, the inequality direction is changed.

$$x>\frac{-5}{-1}$$

Fraction $\frac{-5}{-1}$ can be simplified to $5$ by removing the negative sign from both the numerator and the denominator.

$$x>5$$