1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 32 - 24 | Equatix

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Question

$$3 x 9 - [ 32 - \{ 24 \div ( 8 - 4 - 2 ) \} ]$$

Evaluate

$3x_{9}-20$

Solution Steps

Subtract $4$ from $8$ to get $4$.

$$3x_{9}-\left(32-\frac{24}{4-2}\right)$$

Subtract $2$ from $4$ to get $2$.

$$3x_{9}-\left(32-\frac{24}{2}\right)$$

Divide $24$ by $2$ to get $12$.

$$3x_{9}-\left(32-12\right)$$

Subtract $12$ from $32$ to get $20$.

$$3x_{9}-20$$

Show Solution

Expand

$3x_{9}-20$

Solution Steps

Subtract $4$ from $8$ to get $4$.

$$3x_{9}-\left(32-\frac{24}{4-2}\right)$$

Subtract $2$ from $4$ to get $2$.

$$3x_{9}-\left(32-\frac{24}{2}\right)$$

Divide $24$ by $2$ to get $12$.

$$3x_{9}-\left(32-12\right)$$

Subtract $12$ from $32$ to get $20$.

$$3x_{9}-20$$

Show Solution

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Evaluate

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Solution Steps