Question

$$3 x - 2 y = - 1 \quad x + 4 y = 3$$

Evaluate (complex solution)

$3x-2y=4y-x\text{ and }4y-x=3$

Solve for x

$x = \frac{9}{5} = 1\frac{4}{5} = 1.8$
$y = \frac{6}{5} = 1\frac{1}{5} = 1.2$

Solve for y

$y = \frac{6}{5} = 1\frac{1}{5} = 1.2$
$x = \frac{9}{5} = 1\frac{4}{5} = 1.8$