$$3 x - 72 , 2 x - 4 z + 8 , 2 x - 3 z - 7$$
$6\left(x-24\right)\left(2x-3z-7\right)\left(x-2z+4\right)$
$$-72+3x=3\left(x-24\right)$$ $$8+2x-4z=2\left(x-2z+4\right)$$
$$6\left(x-24\right)\left(2x-3z-7\right)\left(x-2z+4\right)$$
$$12x^{3}-282x^{2}+36xz^{2}+1020xz-312x-864z^{2}-42zx^{2}-288z+4032$$
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$3\left(x-24\right),2\left(x-2z+4\right),2x-3z-7$
