Remove parentheses.
\[\frac{3050}{100}+v-\frac{80}{100}=30+v-\frac{60}{100}\]
Cancel \(v\) on both sides.
\[\frac{3050}{100}-\frac{80}{100}=30-\frac{60}{100}\]
Simplify \(\frac{3050}{100}\) to \(\frac{61}{2}\).
\[\frac{61}{2}-\frac{80}{100}=30-\frac{60}{100}\]
Simplify \(\frac{80}{100}\) to \(\frac{4}{5}\).
\[\frac{61}{2}-\frac{4}{5}=30-\frac{60}{100}\]
Simplify \(\frac{60}{100}\) to \(\frac{3}{5}\).
\[\frac{61}{2}-\frac{4}{5}=30-\frac{3}{5}\]
Simplify \(\frac{61}{2}-\frac{4}{5}\) to \(\frac{297}{10}\).
\[\frac{297}{10}=30-\frac{3}{5}\]
Simplify \(30-\frac{3}{5}\) to \(\frac{147}{5}\).
\[\frac{297}{10}=\frac{147}{5}\]
Since \(\frac{297}{10}=\frac{147}{5}\) is false, there is no solution.
[No Solution]
