Remove parentheses.
\[30\times \frac{50}{100}+V-\frac{80}{100}=30+V-\frac{60}{100}\]
Cancel \(V\) on both sides.
\[30\times \frac{50}{100}-\frac{80}{100}=30-\frac{60}{100}\]
Use this rule: \(a \times \frac{b}{c}=\frac{ab}{c}\).
\[\frac{30\times 50}{100}-\frac{80}{100}=30-\frac{60}{100}\]
Simplify \(30\times 50\) to \(1500\).
\[\frac{1500}{100}-\frac{80}{100}=30-\frac{60}{100}\]
Simplify \(\frac{1500}{100}\) to \(15\).
\[15-\frac{80}{100}=30-\frac{60}{100}\]
Simplify \(\frac{80}{100}\) to \(\frac{4}{5}\).
\[15-\frac{4}{5}=30-\frac{60}{100}\]
Simplify \(\frac{60}{100}\) to \(\frac{3}{5}\).
\[15-\frac{4}{5}=30-\frac{3}{5}\]
Simplify \(15-\frac{4}{5}\) to \(\frac{71}{5}\).
\[\frac{71}{5}=30-\frac{3}{5}\]
Simplify \(30-\frac{3}{5}\) to \(\frac{147}{5}\).
\[\frac{71}{5}=\frac{147}{5}\]
Since \(\frac{71}{5}=\frac{147}{5}\) is false, there is no solution.
[No Solution]
