$$32 \div 4-4(-3+5-6)+12+4-7)$$
$33$
$$8-4\left(-3+5-6\right)+12+4-7$$
$$8-4\left(2-6\right)+12+4-7$$
$$8-4\left(-4\right)+12+4-7$$
$$8-\left(-16\right)+12+4-7$$
$$8+16+12+4-7$$
$$24+12+4-7$$
$$36+4-7$$
$$40-7$$
$$33$$
Show Solution
Hide Solution
$3\times 11$