$$32 ( m + 5 ) ( m ^ { 2 } + 5 m + 3 ) \div 8 \cdot ( m + 6 )$$
$4\left(m+5\right)\left(m+6\right)\left(m^{2}+5m+3\right)$
$$\frac{\left(32m+160\right)\left(m^{2}+5m+3\right)}{8}\left(m+6\right)$$
$$\frac{32m^{3}+320m^{2}+896m+480}{8}\left(m+6\right)$$
$$\frac{\left(32m^{3}+320m^{2}+896m+480\right)\left(m+6\right)}{8}$$
$$\frac{32m^{4}+512m^{3}+2816m^{2}+5856m+2880}{8}$$
Show Solution
Hide Solution
$4m^{4}+64m^{3}+352m^{2}+732m+360$