How to solve 3454 imes320

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3454\times320 | Equatix

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Question

$$3454 \times 320$$

Evaluate

$1105280$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times999}3454\\\underline{\times\phantom{9999}320}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 3454 with 0. Write the result 0 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}3454\\\underline{\times\phantom{9999}320}\\\phantom{\times9999999}0\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 3454 with 2. Write the result 6908 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}3454\\\underline{\times\phantom{9999}320}\\\phantom{\times9999999}0\\\phantom{\times99}6908\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 3454 with 3. Write the result 10362 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}3454\\\underline{\times\phantom{9999}320}\\\phantom{\times9999999}0\\\phantom{\times99}6908\phantom{9}\\\underline{\phantom{\times}10362\phantom{99}}\\\end{array}$$

Now add the intermediate results to get final answer.

Show Solution

Factor

$2^{7}\times 5\times 11\times 157$