How to solve 347 imes421

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 347\times421 | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Question

$$347 \times 421$$

Evaluate

$146087$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times999}347\\\underline{\times\phantom{999}421}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 347 with 1. Write the result 347 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}347\\\underline{\times\phantom{999}421}\\\phantom{\times999}347\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 347 with 2. Write the result 694 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}347\\\underline{\times\phantom{999}421}\\\phantom{\times999}347\\\phantom{\times99}694\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 347 with 4. Write the result 1388 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}347\\\underline{\times\phantom{999}421}\\\phantom{\times999}347\\\phantom{\times99}694\phantom{9}\\\underline{\phantom{\times}1388\phantom{99}}\\\end{array}$$

Now add the intermediate results to get final answer.

$$\begin{array}{c}\phantom{\times999}347\\\underline{\times\phantom{999}421}\\\phantom{\times999}347\\\phantom{\times99}694\phantom{9}\\\underline{\phantom{\times}1388\phantom{99}}\\\phantom{\times}146087\end{array}$$

Show Solution

Factor

$347\times 421$