How to solve 3483x358

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3483x358 | Equatix

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Question

$$3483x358$$

Evaluate

$3483x_{358}$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times999}3483\\\underline{\times\phantom{9999}358}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 3483 with 8. Write the result 27864 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}3483\\\underline{\times\phantom{9999}358}\\\phantom{\times99}27864\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 3483 with 5. Write the result 17415 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}3483\\\underline{\times\phantom{9999}358}\\\phantom{\times99}27864\\\phantom{\times9}17415\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 3483 with 3. Write the result 10449 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}3483\\\underline{\times\phantom{9999}358}\\\phantom{\times99}27864\\\phantom{\times9}17415\phantom{9}\\\underline{\phantom{\times}10449\phantom{99}}\\\end{array}$$

Now add the intermediate results to get final answer.

Show Solution

Differentiate w.r.t. x_358

$3483$

Steps Using Definition of a Derivative

The derivative of $ax^{n}$ is $nax^{n-1}$.

$$3483x_{358}^{1-1}$$

Subtract $1$ from $1$.

$$3483x_{358}^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$3483\times 1$$

For any term $t$, $t\times 1=t$ and $1t=t$.

$$3483$$