How to solve 349 imes215=

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 349\times215= | Equatix

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Question

$$349 \times 215=$$

Evaluate

$75035$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times99}349\\\underline{\times\phantom{99}215}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 349 with 5. Write the result 1745 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}349\\\underline{\times\phantom{99}215}\\\phantom{\times9}1745\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 349 with 1. Write the result 349 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}349\\\underline{\times\phantom{99}215}\\\phantom{\times9}1745\\\phantom{\times9}349\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 349 with 2. Write the result 698 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}349\\\underline{\times\phantom{99}215}\\\phantom{\times9}1745\\\phantom{\times9}349\phantom{9}\\\underline{\phantom{\times}698\phantom{99}}\\\end{array}$$

Now add the intermediate results to get final answer.

$$\begin{array}{c}\phantom{\times99}349\\\underline{\times\phantom{99}215}\\\phantom{\times9}1745\\\phantom{\times9}349\phantom{9}\\\underline{\phantom{\times}698\phantom{99}}\\\phantom{\times}75035\end{array}$$

Show Solution

Factor

$5\times 43\times 349$