How to solve 3498 imes924=

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3498\times924= | Equatix

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Question

$$3498 \times 924=$$

Evaluate

$3232152$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times999}3498\\\underline{\times\phantom{9999}924}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 3498 with 4. Write the result 13992 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}3498\\\underline{\times\phantom{9999}924}\\\phantom{\times99}13992\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 3498 with 2. Write the result 6996 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}3498\\\underline{\times\phantom{9999}924}\\\phantom{\times99}13992\\\phantom{\times99}6996\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 3498 with 9. Write the result 31482 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}3498\\\underline{\times\phantom{9999}924}\\\phantom{\times99}13992\\\phantom{\times99}6996\phantom{9}\\\underline{\phantom{\times}31482\phantom{99}}\\\end{array}$$

Now add the intermediate results to get final answer.

Show Solution

Factor

$2^{3}\times 3^{2}\times 7\times 11^{2}\times 53$