1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 35/24 | Equatix

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Question

$$35/24$$

Evaluate

$\frac{35}{24}\approx 1.458333333$

Steps For Long Division Method

Use the $1^{st}$ digit $3$ from dividend $35$

$$\begin{array}{l}\phantom{24)}\phantom{1}\\24\overline{)35}\\\end{array}$$

Since $3$ is less than $24$, use the next digit $5$ from dividend $35$ and add $0$ to the quotient

$$\begin{array}{l}\phantom{24)}0\phantom{2}\\24\overline{)35}\\\end{array}$$

Use the $2^{nd}$ digit $5$ from dividend $35$

$$\begin{array}{l}\phantom{24)}0\phantom{3}\\24\overline{)35}\\\end{array}$$

Find closest multiple of $24$ to $35$. We see that $1 \times 24 = 24$ is the nearest. Now subtract $24$ from $35$ to get reminder $11$. Add $1$ to quotient.

$$\begin{array}{l}\phantom{24)}01\phantom{4}\\24\overline{)35}\\\phantom{24)}\underline{\phantom{}24\phantom{}}\\\phantom{24)}11\\\end{array}$$

Since $11$ is less than $24$, stop the division. The reminder is $11$. The topmost line $01$ is the quotient. Remove all zeros at the start of the quotient to get the actual quotient $1$.

$$\text{Quotient: }1$$ $$\text{Reminder: }11$$

Show Solution

Factor

$\frac{5 \cdot 7}{2 ^ {3} \cdot 3} = 1\frac{11}{24} = 1.4583333333333333$