How to solve 35-[16-(14-35+2)]

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 35-[16-(14-35+2)] | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$35-[16-(14-35+2)]$$

Evaluate

$0$

Solution Steps

Subtract $35$ from $14$ to get $-21$.

$$35-\left(16-\left(-21+2\right)\right)$$

Add $-21$ and $2$ to get $-19$.

$$35-\left(16-\left(-19\right)\right)$$

The opposite of $-19$ is $19$.

$$35-\left(16+19\right)$$

Add $16$ and $19$ to get $35$.

$$35-35$$

Subtract $35$ from $35$ to get $0$.

$$0$$

Show Solution

Factor

$0$

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