$$3.5\times6+80\div3\_0,1$$
$1,3,\frac{110}{3}$
$$sort(3,30+\frac{20}{3}-0,1)$$
$$sort(3,\frac{90}{3}+\frac{20}{3}-0,1)$$
$$sort(3,\frac{90+20}{3}-0,1)$$
$$sort(3,\frac{110}{3}-0,1)$$
$$sort(3,\frac{110}{3},1)$$
$$3,\frac{110}{3},1$$
$$3$$
$$3,\frac{110}{3}$$
$$1,3,\frac{110}{3}$$
Show Solution
Hide Solution
$3,\frac{110}{3},1$