How to solve 35742 *3728

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 35742 *3728 | Equatix

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Question

$$35742 \times 3728$$

Evaluate

$133246176$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times9999}35742\\\underline{\times\phantom{99999}3728}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 35742 with 8. Write the result 285936 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times9999}35742\\\underline{\times\phantom{99999}3728}\\\phantom{\times999}285936\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 35742 with 2. Write the result 71484 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times9999}35742\\\underline{\times\phantom{99999}3728}\\\phantom{\times999}285936\\\phantom{\times999}71484\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 35742 with 7. Write the result 250194 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times9999}35742\\\underline{\times\phantom{99999}3728}\\\phantom{\times999}285936\\\phantom{\times999}71484\phantom{9}\\\phantom{\times9}250194\phantom{99}\\\end{array}$$

Now multiply the first number with the $4^{th}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 35742 with 3. Write the result 107226 at the end leaving 3 spaces to the right like this.

$$\begin{array}{c}\phantom{\times9999}35742\\\underline{\times\phantom{99999}3728}\\\phantom{\times999}285936\\\phantom{\times999}71484\phantom{9}\\\phantom{\times9}250194\phantom{99}\\\underline{\phantom{\times}107226\phantom{999}}\\\end{array}$$

Now add the intermediate results to get final answer.

Show Solution

Factor

$2^{5}\times 3\times 7\times 23\times 37\times 233$