How to solve 38 imes201

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 38\times201 | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Question

$$38 \times 201$$

Evaluate

$7638$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times99}38\\\underline{\times\phantom{9}201}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 38 with 1. Write the result 38 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}38\\\underline{\times\phantom{9}201}\\\phantom{\times99}38\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 38 with 0. Write the result 0 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}38\\\underline{\times\phantom{9}201}\\\phantom{\times99}38\\\phantom{\times999}0\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 38 with 2. Write the result 76 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}38\\\underline{\times\phantom{9}201}\\\phantom{\times99}38\\\phantom{\times999}0\phantom{9}\\\underline{\phantom{\times}76\phantom{99}}\\\end{array}$$

Now add the intermediate results to get final answer.

$$\begin{array}{c}\phantom{\times99}38\\\underline{\times\phantom{9}201}\\\phantom{\times99}38\\\phantom{\times999}0\phantom{9}\\\underline{\phantom{\times}76\phantom{99}}\\\phantom{\times}7638\end{array}$$

Show Solution

Factor

$2\times 3\times 19\times 67$