How to solve 38352 imes428

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 38352\times428 | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Question

$$38352 \times 428$$

Evaluate

$16414656$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times999}38352\\\underline{\times\phantom{99999}428}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 38352 with 8. Write the result 306816 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}38352\\\underline{\times\phantom{99999}428}\\\phantom{\times99}306816\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 38352 with 2. Write the result 76704 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}38352\\\underline{\times\phantom{99999}428}\\\phantom{\times99}306816\\\phantom{\times99}76704\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 38352 with 4. Write the result 153408 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}38352\\\underline{\times\phantom{99999}428}\\\phantom{\times99}306816\\\phantom{\times99}76704\phantom{9}\\\underline{\phantom{\times}153408\phantom{99}}\\\end{array}$$

Now add the intermediate results to get final answer.

Show Solution

Factor

$2^{6}\times 3\times 17\times 47\times 107$