How to solve 384 imes120

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 384\times120 | Equatix

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Question

$$384 \times 120$$

Evaluate

$46080$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times99}384\\\underline{\times\phantom{99}120}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 384 with 0. Write the result 0 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}384\\\underline{\times\phantom{99}120}\\\phantom{\times99999}0\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 384 with 2. Write the result 768 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}384\\\underline{\times\phantom{99}120}\\\phantom{\times99999}0\\\phantom{\times9}768\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 384 with 1. Write the result 384 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}384\\\underline{\times\phantom{99}120}\\\phantom{\times99999}0\\\phantom{\times9}768\phantom{9}\\\underline{\phantom{\times}384\phantom{99}}\\\end{array}$$

Now add the intermediate results to get final answer.

$$\begin{array}{c}\phantom{\times99}384\\\underline{\times\phantom{99}120}\\\phantom{\times99999}0\\\phantom{\times9}768\phantom{9}\\\underline{\phantom{\times}384\phantom{99}}\\\phantom{\times}46080\end{array}$$

Show Solution

Factor

$2^{10}\times 3^{2}\times 5$