How to solve 39365 X298

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 39365 X298 | Equatix

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Question

$$39365 \times 298$$

Evaluate

$11730770$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times999}39365\\\underline{\times\phantom{99999}298}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 39365 with 8. Write the result 314920 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}39365\\\underline{\times\phantom{99999}298}\\\phantom{\times99}314920\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 39365 with 9. Write the result 354285 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}39365\\\underline{\times\phantom{99999}298}\\\phantom{\times99}314920\\\phantom{\times9}354285\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 39365 with 2. Write the result 78730 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}39365\\\underline{\times\phantom{99999}298}\\\phantom{\times99}314920\\\phantom{\times9}354285\phantom{9}\\\underline{\phantom{\times9}78730\phantom{99}}\\\end{array}$$

Now add the intermediate results to get final answer.

Show Solution

Factor

$2\times 5\times 149\times 7873$