How to solve 3a-[a+b-(2a+b)]

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3a-[a+b-(2a+b)] | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$3a-[a+b-(2a+b)]$$

Evaluate

$4a$

Solution Steps

To find the opposite of $2a+b$, find the opposite of each term.

$$3a-\left(a+b-2a-b\right)$$

Combine $a$ and $-2a$ to get $-a$.

$$3a-\left(-a+b-b\right)$$

Combine $b$ and $-b$ to get $0$.

$$3a-\left(-a\right)$$

The opposite of $-a$ is $a$.

$$3a+a$$

Combine $3a$ and $a$ to get $4a$.

$$4a$$

Show Solution

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$4a$

Solution Steps

To find the opposite of $2a+b$, find the opposite of each term.

$$3a-\left(a+b-2a-b\right)$$

Combine $a$ and $-2a$ to get $-a$.

$$3a-\left(-a+b-b\right)$$

Combine $b$ and $-b$ to get $0$.

$$3a-\left(-a\right)$$

The opposite of $-a$ is $a$.

$$3a+a$$

Combine $3a$ and $a$ to get $4a$.

$$4a$$

Show Solution

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Question

Evaluate

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Solution Steps