How to solve 3b-6=(-9b)/3+12

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3b-6=(-9b)/3+12 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$3b-6=(-9b)/3+12$$

Solve for b

$b=3$

Steps for Solving Linear Equation

Multiply both sides of the equation by $3$.

$$9b-18=-9b+36$$

Add $9b$ to both sides.

$$9b-18+9b=36$$

Combine $9b$ and $9b$ to get $18b$.

$$18b-18=36$$

Add $18$ to both sides.

$$18b=36+18$$

Add $36$ and $18$ to get $54$.

$$18b=54$$

Divide both sides by $18$.

$$b=\frac{54}{18}$$

Divide $54$ by $18$ to get $3$.

$$b=3$$

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Question

Solve for b

Steps for Solving Linear Equation