How to solve 3p+5(2-p)=16

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3p+5(2-p)=16 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$3p+5(2-p)=16$$

Solve for p

$p=-3$

Steps for Solving Linear Equation

Use the distributive property to multiply $5$ by $2-p$.

$$3p+10-5p=16$$

Combine $3p$ and $-5p$ to get $-2p$.

$$-2p+10=16$$

Subtract $10$ from both sides.

$$-2p=16-10$$

Subtract $10$ from $16$ to get $6$.

$$-2p=6$$

Divide both sides by $-2$.

$$p=\frac{6}{-2}$$

Divide $6$ by $-2$ to get $-3$.

$$p=-3$$

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Question

Solve for p

Steps for Solving Linear Equation