Question

$$3x=28+8; 5t-3t=3+5; 5x+9=5+3x; 47+3=6+2z; 2x-1=16\div x; x=\frac{4}{5}(x+10)$$

Answer

No Solution

Solution


Solve for \(x\) in \(3x=28+8\).
\[x=12\]
Substitute \(x=12\) into \(5t-3t=3+5\).
\[2t=8\]
Substitute \(x=12\) into \(5x+9=5+3x\).
\[69=41\]
Since \(69=41\) is not true, this is an inconsistent system.
No Solution