How to solve 3x-1 >= x-3

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3x-1 >= x-3 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$3x-1 \geq x-3$$

Solve for x

$x\geq -1$

Solution Steps

Subtract $x$ from both sides.

$$3x-1-x\geq -3$$

Combine $3x$ and $-x$ to get $2x$.

$$2x-1\geq -3$$

Add $1$ to both sides.

$$2x\geq -3+1$$

Add $-3$ and $1$ to get $-2$.

$$2x\geq -2$$

Divide both sides by $2$. Since $2$ is positive, the inequality direction remains the same.

$$x\geq \frac{-2}{2}$$

Divide $-2$ by $2$ to get $-1$.

$$x\geq -1$$

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Question

Solve for x

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