Question

$$3x-1x-3; \frac{3t-2}{4}-\frac{2t+3}{3}\cdot\frac{2}{3}-t$$

Answer

3*x-x-3;(3*t-2)/4-(2*(2*t+3))/9-t

Solution


Simplify  \(\frac{2t+3}{3}\times \frac{2}{3}\)  to  \(\frac{2(2t+3)}{9}\).
\[\begin{aligned}&3x-x-3\\&\frac{3t-2}{4}-\frac{2(2t+3)}{9}-t\end{aligned}\]