How to solve 3x-2 > x-5

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3x-2 > x-5 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$3x-2 > x-5$$

Solve for x

$x>-\frac{3}{2}$

Solution Steps

Subtract $x$ from both sides.

$$3x-2-x>-5$$

Combine $3x$ and $-x$ to get $2x$.

$$2x-2>-5$$

Add $2$ to both sides.

$$2x>-5+2$$

Add $-5$ and $2$ to get $-3$.

$$2x>-3$$

Divide both sides by $2$. Since $2$ is positive, the inequality direction remains the same.

$$x>-\frac{3}{2}$$

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Question

Solve for x

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