How to solve 3x-2(6x-3)=42

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3x-2(6x-3)=42 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$3x-2(6x-3)=42$$

Solve for x

$x=-4$

Steps for Solving Linear Equation

Use the distributive property to multiply $-2$ by $6x-3$.

$$3x-12x+6=42$$

Combine $3x$ and $-12x$ to get $-9x$.

$$-9x+6=42$$

Subtract $6$ from both sides.

$$-9x=42-6$$

Subtract $6$ from $42$ to get $36$.

$$-9x=36$$

Divide both sides by $-9$.

$$x=\frac{36}{-9}$$

Divide $36$ by $-9$ to get $-4$.

$$x=-4$$

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Question

Solve for x

Steps for Solving Linear Equation