How to solve 3x-5 > 10

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3x-5 > 10 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$3x-5 > 10$$

Solve for x

$x>5$

Solution Steps

Add $5$ to both sides.

$$3x>10+5$$

Add $10$ and $5$ to get $15$.

$$3x>15$$

Divide both sides by $3$. Since $3$ is positive, the inequality direction remains the same.

$$x>\frac{15}{3}$$

Divide $15$ by $3$ to get $5$.

$$x>5$$

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Solve for x

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