How to solve 3x-7 < 5

Q: How to solve 3x-7 < 5

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3x-7 < 5 | Equatix

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3(r+2s)=2t-4

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3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$3x-7 < 5$$

Solve for x

$x<4$

Solution Steps

Add $7$ to both sides.

$$3x<5+7$$

Add $5$ and $7$ to get $12$.

$$3x<12$$

Divide both sides by $3$. Since $3$ is positive, the inequality direction remains the same.

$$x<\frac{12}{3}$$

Divide $12$ by $3$ to get $4$.

$$x<4$$

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