How to solve 3x-7y+4=0

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3x-7y+4=0 | Equatix

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$3x-7y+4=0$$

Solve for x

$x=\frac{7y-4}{3}$

Steps for Solving Linear Equation

Add $7y$ to both sides. Anything plus zero gives itself.

$$3x+4=7y$$

Subtract $4$ from both sides.

$$3x=7y-4$$

Divide both sides by $3$.

$$\frac{3x}{3}=\frac{7y-4}{3}$$

Dividing by $3$ undoes the multiplication by $3$.

$$x=\frac{7y-4}{3}$$

Show Solution

Solve for y

$y=\frac{3x+4}{7}$

Steps for Solving Linear Equation

Subtract $3x$ from both sides. Anything subtracted from zero gives its negation.

$$-7y+4=-3x$$

Subtract $4$ from both sides.

$$-7y=-3x-4$$

Divide both sides by $-7$.

$$\frac{-7y}{-7}=\frac{-3x-4}{-7}$$

Dividing by $-7$ undoes the multiplication by $-7$.

$$y=\frac{-3x-4}{-7}$$

Divide $-3x-4$ by $-7$.

$$y=\frac{3x+4}{7}$$

Show Solution

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Question

Solve for x

Steps for Solving Linear Equation

Solve for y

Steps for Solving Linear Equation