$$3x-(8-x)=3+[2x-(1-x)]$$
$x=10$
$$3x-8-\left(-x\right)=3+2x-\left(1-x\right)$$
$$3x-8+x=3+2x-\left(1-x\right)$$
$$4x-8=3+2x-\left(1-x\right)$$
$$4x-8=3+2x-1-\left(-x\right)$$
$$4x-8=3+2x-1+x$$
$$4x-8=2+2x+x$$
$$4x-8=2+3x$$
$$4x-8-3x=2$$
$$x-8=2$$
$$x=2+8$$
$$x=10$$
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