Solve [3x-(-10)+10-(-18)+30-5x] | Equatix - Math Solver

Fractions & Decimals

Ratios & Proportions

Basic Number Theory

Integers & Absolute Values

Factors & Multiples

Prime Factorization

Basic Equations & Inequalities

Coordinate Plane & Graphing

Linear Equations & Inequalities

Quadratic Equations

Polynomials & Factoring

Functions & Graphs

Systems of Equations

Trigonometric Functions

Trigonometric Identities & Equations

Right Triangle Trigonometry

Graphing Trigonometric Functions

Limits & Continuity

Derivatives & Applications

Integrals & Applications

Series & Sequences

Multivariable Calculus

Functions & Graphs

Polynomial & Rational Functions

Exponential & Logarithmic Functions

Sequences & Series

Descriptive Statistics

Normal Distribution

Hypothesis Testing

Regression Analysis

Linear Programming

Sets & Counting

Eigenvalues & Eigenvectors

Linear Transformations

Atomic Structure

Thermochemistry

Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$[3x-(-10)+10-(-18)+30-5x]$$

Evaluate

$68-2x$

Solution Steps

The opposite of $-10$ is $10$.

$$3x+10+10-\left(-18\right)+30-5x$$

Add $10$ and $10$ to get $20$.

$$3x+20-\left(-18\right)+30-5x$$

The opposite of $-18$ is $18$.

$$3x+20+18+30-5x$$

Add $20$ and $18$ to get $38$.

$$3x+38+30-5x$$

Add $38$ and $30$ to get $68$.

$$3x+68-5x$$

Combine $3x$ and $-5x$ to get $-2x$.

$$-2x+68$$

Factor

$2\left(34-x\right)$