$$3x(x+5)+4 \geq 3 { x }^{ 2 } +2(x+4)$$
$x\geq \frac{4}{13}$
$$3x^{2}+15x+4\geq 3x^{2}+2\left(x+4\right)$$
$$3x^{2}+15x+4\geq 3x^{2}+2x+8$$
$$3x^{2}+15x+4-3x^{2}\geq 2x+8$$
$$15x+4\geq 2x+8$$
$$15x+4-2x\geq 8$$
$$13x+4\geq 8$$
$$13x\geq 8-4$$
$$13x\geq 4$$
$$x\geq \frac{4}{13}$$
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