How to solve 3x+1)^ 3 =64

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3x+1)^ 3 =64 | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Question

$$3x+1)^{3}=64$$

Differentiate w.r.t. x

$3$

Steps Using Derivative Rule for Sum

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is $0$. The derivative of $ax^{n}$ is $nax^{n-1}$.

$$3x^{1-1}$$

Subtract $1$ from $1$.

$$3x^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$3\times 1$$

For any term $t$, $t\times 1=t$ and $1t=t$.

$$3$$

Show Solution

Evaluate

$3x+1$