How to solve 3x+2 > (x-2)/(2)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3x+2 > (x-2)/(2) | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$3x+2 > \frac{ x-2 }{ 2 }$$

Solve for x

$x>-\frac{6}{5}$

Solution Steps

Multiply both sides of the equation by $2$. Since $2$ is positive, the inequality direction remains the same.

$$6x+4>x-2$$

Subtract $x$ from both sides.

$$6x+4-x>-2$$

Combine $6x$ and $-x$ to get $5x$.

$$5x+4>-2$$

Subtract $4$ from both sides.

$$5x>-2-4$$

Subtract $4$ from $-2$ to get $-6$.

$$5x>-6$$

Divide both sides by $5$. Since $5$ is positive, the inequality direction remains the same.

$$x>-\frac{6}{5}$$

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Question

Solve for x

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