How to solve 3x + 4 = 0; x =

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3x + 4 = 0; x = | Equatix

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$$3x+4=0; x=$$

$y = -\frac{4}{3} = -1\frac{1}{3} \approx -1.333333333$

Consider the first equation. Subtract $4$ from both sides. Anything subtracted from zero gives its negation.

$$3x=-4$$

Divide both sides by $3$.

$$x=-\frac{4}{3}$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=-\frac{4}{3}$$

The system is now solved.

$$x=-\frac{4}{3}$$ $$y=-\frac{4}{3}$$