Solve 3x + 6/5 = 6x + 3/25 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$3x+\frac{6}{5}=6x+\frac{3}{25}$$

Solve for x

$x=\frac{9}{25}=0.36$

Steps for Solving Linear Equation

Subtract $6x$ from both sides.

$$3x+\frac{6}{5}-6x=\frac{3}{25}$$

Combine $3x$ and $-6x$ to get $-3x$.

$$-3x+\frac{6}{5}=\frac{3}{25}$$

Subtract $\frac{6}{5}$ from both sides.

$$-3x=\frac{3}{25}-\frac{6}{5}$$

Least common multiple of $25$ and $5$ is $25$. Convert $\frac{3}{25}$ and $\frac{6}{5}$ to fractions with denominator $25$.

$$-3x=\frac{3}{25}-\frac{30}{25}$$

Since $\frac{3}{25}$ and $\frac{30}{25}$ have the same denominator, subtract them by subtracting their numerators.

$$-3x=\frac{3-30}{25}$$

Subtract $30$ from $3$ to get $-27$.

$$-3x=-\frac{27}{25}$$

Divide both sides by $-3$.

$$x=\frac{-\frac{27}{25}}{-3}$$

Express $\frac{-\frac{27}{25}}{-3}$ as a single fraction.

$$x=\frac{-27}{25\left(-3\right)}$$

Multiply $25$ and $-3$ to get $-75$.

$$x=\frac{-27}{-75}$$

Reduce the fraction $\frac{-27}{-75}$ to lowest terms by extracting and canceling out $-3$.

$$x=\frac{9}{25}$$