Question

$$3x+ \sqrt{ { 6 }^{ 2 } + { 8 }^{ 2 } } =8 \times x$$

Answer

x=2

Solution


Simplify  \({6}^{2}\)  to  \(36\).
\[3x+\sqrt{36+{8}^{2}}=8x\]
Simplify  \({8}^{2}\)  to  \(64\).
\[3x+\sqrt{36+64}=8x\]
Simplify  \(36+64\)  to  \(100\).
\[3x+\sqrt{100}=8x\]
Since \(10\times 10=100\), the square root of \(100\) is \(10\).
\[3x+10=8x\]
Subtract \(3x\) from both sides.
\[10=8x-3x\]
Simplify  \(8x-3x\)  to  \(5x\).
\[10=5x\]
Divide both sides by \(5\).
\[\frac{10}{5}=x\]
Simplify  \(\frac{10}{5}\)  to  \(2\).
\[2=x\]
Switch sides.
\[x=2\]