$$3x+y-6=0$$
$x=-\frac{y}{3}+2$
$$3x-6=-y$$
$$3x=-y+6$$
$$3x=6-y$$
$$\frac{3x}{3}=\frac{6-y}{3}$$
$$x=\frac{6-y}{3}$$
$$x=-\frac{y}{3}+2$$
Show Solution
Hide Solution
$y=6-3x$
$$y-6=-3x$$
$$y=-3x+6$$
