$$3x^{3}\cdot4x^{-4}y^{-3}$$
$\frac{12}{xy^{3}}$
$$3x^{-1}\times 4y^{-3}$$
$$12x^{-1}y^{-3}$$
Show Solution
Hide Solution
$-\frac{12}{x^{2}y^{3}}$
