$$3xy+3-3x-3y$$
$3\left(x-1\right)\left(y-1\right)$
$$3\left(xy+1-x-y\right)$$
$$x\left(y-1\right)-\left(y-1\right)$$
$$\left(y-1\right)\left(x-1\right)$$
$$3\left(x-1\right)\left(y-1\right)$$
Show Solution
Hide Solution