$$3y-5y+7y=$$
$5y$
$$-2y+7y$$
$$5y$$
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$5$
$$\frac{\mathrm{d}}{\mathrm{d}y}(-2y+7y)$$
$$\frac{\mathrm{d}}{\mathrm{d}y}(5y)$$
$$5y^{1-1}$$
$$5y^{0}$$
$$5\times 1$$
$$5$$