How to solve 3y-(2-5y)=0

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3y-(2-5y)=0 | Equatix

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$$3y-(2-5y)=0$$

$y=\frac{1}{4}=0.25$

To find the opposite of $2-5y$, find the opposite of each term.

$$3y-2-\left(-5y\right)=0$$

The opposite of $-5y$ is $5y$.

$$3y-2+5y=0$$

Combine $3y$ and $5y$ to get $8y$.

$$8y-2=0$$

Add $2$ to both sides. Anything plus zero gives itself.

$$8y=2$$

Divide both sides by $8$.

$$y=\frac{2}{8}$$

Reduce the fraction $\frac{2}{8}$ to lowest terms by extracting and canceling out $2$.

$$y=\frac{1}{4}$$