How to solve 3y + 8 = 22; y =

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3y + 8 = 22; y = | Equatix

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$$3y+8=22; y=$$

$z = \frac{14}{3} = 4\frac{2}{3} \approx 4.666666667$

Consider the first equation. Subtract $8$ from both sides.

$$3y=22-8$$

Subtract $8$ from $22$ to get $14$.

$$3y=14$$

Divide both sides by $3$.

$$y=\frac{14}{3}$$

Consider the second equation. Insert the known values of variables into the equation.

$$z=\frac{14}{3}$$

The system is now solved.

$$y=\frac{14}{3}$$ $$z=\frac{14}{3}$$