$$3y+ \frac{ 5 }{ 3 } = \frac{ 18 }{ 3 } -y$$
$y = \frac{13}{12} = 1\frac{1}{12} \approx 1.083333333$
$$3y+\frac{5}{3}=6-y$$
$$3y+\frac{5}{3}+y=6$$
$$4y+\frac{5}{3}=6$$
$$4y=6-\frac{5}{3}$$
$$4y=\frac{18}{3}-\frac{5}{3}$$
$$4y=\frac{18-5}{3}$$
$$4y=\frac{13}{3}$$
$$y=\frac{\frac{13}{3}}{4}$$
$$y=\frac{13}{3\times 4}$$
$$y=\frac{13}{12}$$
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