How to solve expressions 6 2 b

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve expressions 6 2 b | Equatix

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$$4 a + 6 b , 2 b + 3 c$$

$2\left(2a+3b\right)\left(2b+3c\right)$

Factor the expressions that are not already factored.

$$4a+6b=2\left(2a+3b\right)$$

Identify all the factors and their highest power in all expressions. Multiply the highest powers of these factors to get the least common multiple.

$$2\left(2a+3b\right)\left(2b+3c\right)$$

Expand the expression.

$$8ab+12ac+12b^{2}+18bc$$

$4a+6b,2b+3c$