$$4 a ^ { 3 } + 3 a ^ { 2 } - a - 5 \cdot 4$$
$12a^{2}+6a-1$
$$\frac{\mathrm{d}}{\mathrm{d}a}(4a^{3}+3a^{2}-a-20)$$
$$3\times 4a^{3-1}+2\times 3a^{2-1}-a^{1-1}$$
$$12a^{3-1}+2\times 3a^{2-1}-a^{1-1}$$
$$12a^{2}+2\times 3a^{2-1}-a^{1-1}$$
$$12a^{2}+6a^{2-1}-a^{1-1}$$
$$12a^{2}+6a^{1}-a^{1-1}$$
$$12a^{2}+6a^{1}-a^{0}$$
$$12a^{2}+6a-a^{0}$$
$$12a^{2}+6a-1$$
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$4a^{3}+3a^{2}-a-20$
$$4a^{3}+3a^{2}-a-20$$
