How to solve 4(1)^(2)+3(1)-1

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 4(1)^(2)+3(1)-1 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$4 { 1 }^{ 2 } +3(1)-1$$

Evaluate

$6$

Solution Steps

Calculate $1$ to the power of $2$ and get $1$.

$$4\times 1+3\times 1-1$$

Multiply $4$ and $1$ to get $4$.

$$4+3\times 1-1$$

Multiply $3$ and $1$ to get $3$.

$$4+3-1$$

Add $4$ and $3$ to get $7$.

$$7-1$$

Subtract $1$ from $7$ to get $6$.

$$6$$

Show Solution

Factor

$2\times 3$

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Question

Evaluate

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Factor